Question

Find the area of the convex polygon in the plane with vertices at the points whose coordinates (-2,3), (1,10), (5,10), (8,7) and (4,0)... yes.. I have attempt it. I need help on it though! I graphed the shape and it looks like a house but diagonal on the first quadrant.

Answer 1

Oh and it also passes the 2nd quadrant too.

Answer 2

you break it into rectangles and triangles . the two triangles make a rectangle with an area
\[\sqrt 42.5*\sqrt 86.5=\sqrt 3676.25\]the rectangle has an area 65.
wheuh!!! That took forever!!!

Answer 3

Thank you so much! You earned a medal for your hard work :) very much appreciate it!