Question

Solve equation by factoring.
4) x^2 - 15x=-56


3) a^2- 64=0

I just want to know how you to move numbers to the other side of the equal sign.

Answer 1

first you have to move all numbers to one side:


x^2-15x+56=0

Answer 2

@mariannu for a, if you were to add 56 (or subtract -56) from each side, you would get what dave said, it's really just that easy.

Answer 3

then you are going to find common factors:

(x- 8)(x-7 )=0

then set each side to 0:

x-8=0 and x-7=0

solve for x on both sides, and x=8 and x=7

Answer 4

but this is solving each equation by factorin I am solving quadratics. not that.

Answer 5

Or my bad Xd your doing exactly what it is? XD

Answer 6

hahaha i was gonna say, you asked for factoring, which is one way to solve quadratics haha
do you need help solving the second one?

Answer 7

Because the other one I did It was 5v^2=-30v-40 XD and I gott v=+- jsqaure root of -14

Answer 8

and I didn't have to move it to the other side. What is the easiet way to solve a^2 -64=0
and x^2-15x=-56

Answer 9

I just don't knwo how to solve these type of quadratrics : p XD accept the one that I have the answer for I know how to do that type of problem

Answer 10

the easiest way to solve x^2-15=-56 is how i outlined it above, realizing you have to move -56 to the other side is honestly the trickiest part. and a^2-64=0 is the same thing

the first basic rule to solving quadratics is setting it to zero. Ill walk you through the second problem you have and explain what i am doing with each step

Answer 11

a^2-64=0 --------1) already set to 0 so we are good there
(a- )(a+ )=0 -------2) since you know that a is squared break it up, and because 64 is
negative you know one will be positive and one will be negative.
64/8=8 -----------3) testing for the factor (i chose 8 first because 8^2 is 64)
(a+8)(a-8)=0-------4) plug in the factor
(a+8)=0 and (a-8)=0 ----5)set both sides to 0
a=0-8 and a=0-8---6)solve both new found equations
a=-8 ---------------7)-8 is the answer

Answer 12

Wouldn't it be like this? the answer/