Please Can you Check My approaches of these card probabilities are correct with assumptions that:
Cards are dealt from a well shuffled standard deck means cards are drawn at random without replacement. Find the chance that:
iQ) The first card is not a heart?
iA) Compliment Rule; Solution 52 cards; of these there are 4 Aces.
P(not A)= 1-P(A)= P(A first card not an Ace)= 1- P(A first card is an Ace)=1-(4/52)= (52-4)/52=48/52=12/13=0.923=92.30%
iiQ) The 10th card is the ace of spades.
iiA) By symmetry in card shuffling
P(A it's Ace of Heart)= 1/52

ivQ) the 32nd card is red, given that the 51st and 52nd cards are red
ivA) By conditional or unconditional?

standard deck consists of 52 cards, 26 of which are red. Cards are dealt one by one without replacement.
P(A the 32nd card is red 24/50)\P(B of 51st 26/52and P(C of 52nd 25/51 Cards are red) =24/50*26/52*25/51=0.1176

vQ) The 51st card is red, given that the 32nd and 52nd cards are red
vA) P(A the 51st card is red 24/50)= P(B of 32nd 26/52 and P(C of 52nd 25/51 Cards are red) =24/50*26/52*25/51= 0.1176

Question

Please Can you Check My approaches of these  card probabilities are correct with assumptions that:
Cards are dealt from a well shuffled standard deck means cards are drawn at random without replacement. Find the chance that:
iQ) The first card is not a heart?
iA) Compliment Rule;  Solution 52 cards; of these there are 4 Aces. 
P(not A)= 1-P(A)=  P(A first card not an Ace)= 1- P(A first card is an Ace)=1-(4/52)= (52-4)/52=48/52=12/13=0.923=92.30%
iiQ) The 10th card is the ace of spades.
iiA) By symmetry in card shuffling
    P(A it's Ace of Heart)= 1/52

ivQ) the 32nd card is red, given that the 51st and 52nd cards are red
ivA)  By  conditional or unconditional?
	
 standard deck consists of 52 cards, 26 of which are red. Cards are dealt one by one without  replacement.
P(A the 32nd card is red 24/50)\P(B of 51st 26/52and P(C of 52nd 25/51 Cards are red) =24/50*26/52*25/51=0.1176

vQ) The 51st card is red, given that the 32nd and 52nd cards are red
vA) P(A the 51st card is red 24/50)= P(B of 32nd 26/52 and P(C of 52nd 25/51 Cards are red) =24/50*26/52*25/51= 0.1176

anonymous · Answer

iiA is correct .but i A ans 12/13 is not crct

anonymous · Answer

An urn contains 10 white balls and 5 blue balls. Draws are made repeatedly from the urn as follows. On each draw, a ball is drawn and its color noted; then it is replaced in the urn along with 3 more balls of its color.

PROBLEM 4A

Find the chance that the first ball drawn is blue.

anonymous · Answer

A person is selected at random from a population that has the following characteristics:

    65% of the people are men; the others are women

    12% of the men are smokers

    7% of the women are smokers

PROBLEM 2A

Find the chance that the selected person is a non-smoker, given that the person is a man.

(Decimal answer, please, correct to four decimal places.)

anonymous · Answer

any one z thr to reply

anonymous · Answer

A person is selected at random from a population that has the following characteristics:

    65% of the people are men; the others are women

    12% of the men are smokers

    7% of the women are smokers

PROBLEM 2A

Find the chance that the selected person is a non-smoker, given that the person is a man.

(Decimal answer, please, correct to four decimal places.)