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OpenStudy (anonymous):
Factor completely: 64a^2b^3 − 40ab
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OpenStudy (anonymous):
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OpenStudy (anonymous):
sorry wrong post
OpenStudy (anonymous):
You can directly see the common factors, 64a^(2)b^(3)-40ab GCF of 8ab from 64a^(2)b^(3)-40ab. 8ab(8ab^(2)-5)
OpenStudy (anonymous):
Factor completely: −6x^3y + 9x^2y^2 − 12xy^3
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
the factor complete is Factor completely: -6x^3y+9x^2y^2-12xy^3 C. -3xy(2x^2-3xy+4y^2)
OpenStudy (anonymous):
you got that @allie_bear22
OpenStudy (anonymous):
yea thnx
OpenStudy (anonymous):
np annytime
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