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Mathematics 12 Online
OpenStudy (anonymous):

Factor completely: 2ax + 4bx − 3ay − 6by

OpenStudy (anonymous):

oo i know this one i did it :DD

OpenStudy (nathan917):

Easy Factor the It by grouping: 2ax + 4bx - 3ay - 6by 2x(a + 2b) - 3y(a + 2b) (2x - 3y)(a + 2b)

OpenStudy (anonymous):

Factor the first by grouping: 2ax + 4bx - 3ay - 6by 2x(a + 2b) - 3y(a + 2b) (2x - 3y)(a + 2b) Factor the second by removing a common term, then by regular trinomial rules: 2x^2 - 6x - 56 2(x^2 - 3x - 28) 2(x - 7)(x + 4) Happy to help

OpenStudy (nathan917):

So Do i its (2x - 3y)(a + 2b) :P

OpenStudy (anonymous):

thnx

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