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Mathematics 17 Online
OpenStudy (anonymous):

HELP!! Where is the transverse axis for the hyperbola? x^2-4y^2=16

OpenStudy (amistre64):

the transverse axis holds the vertexes right?

OpenStudy (amistre64):

you might want to observe that when x=0, there is no "real" solution for y that fits|dw:1366312951767:dw| so our solutions have to be parallel to the x axis

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