Question

please help me!!!!
5 2 5
-------- - ----- = -----
x^2-7x+12 3-x x-4

Answer 1

please can someone help!!!!

Answer 2

Factor the first denominator.

Answer 3

(x-4)(x-3)

Answer 4

For the second fraction, please note that:
\[- \frac{2}{3-x}=+\frac{2}{x-3}\]

Answer 5

Now, write each fraction with the common denominator (x-4)(x-3)

Answer 6

how if the end of the equations doesnt have the same
lcd

Answer 7

\[\frac{5}{x^2-7 x+12}-\frac{2}{3-x}-\frac{5}{x-4}\neq 0 \]\[\frac{1}{x-3}\neq 0 \]

Answer 8

so the answer is no solution?

Answer 9

Yes.

Answer 10

ohhhh