Question

Perform the division.-36r^4+40r^324r^2+23r+7/-4r

Answer 1

I'll assume that the term in r^2 is being added.

well it can be simplifed to

\[\frac{-36r^4}{-4r} + \frac{40r^3}{-4r} + \frac{24r^2}{-4r} + \frac{23r}{-4r} + \frac{7}{-4r}\]

this will allow the expression to be simplified term by term.

The last term will be the remainder.

and the constant term will be a fraction.

hope this helps.

Answer 2

that helped a lot thank you!