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Rewrite the equation 9x^2−54x+97 = 0 in the form A(x+B)^2+C=0 by completing the square so that A is the greatest common factor and B and C are real numbers. Which i've figured out A = 9 B = -3 C = 16 Then here is the problem the solutions: 3-4i/3 3+4i/3 At least I think those are the solutions I just can't figure out the syntax
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\[ 9x^2−54x+97 = 0\] \[9(x^2-6x)=-97\] \[
at this point i would divide by 9
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