Question

solve the system of equations by using the elimination method.
{4x^2+3y^2=12
{5x^2+6y^2=30

Answer 1

multiply the 1st equation by 2 and subtract the 2nd equation, this will eliminate y^2

so you have

\[8x^2 + 6y^2 = 24\]

\[-5x^2 - 6y^2 = -30\]
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\[3x^2 = -6\]

this is interesting as you will have a complex solution.

when you have x, substitute both values to find y.

Answer 2

thank you

Answer 3

got it no solution