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ln(x+2)+ln(x)=ln(35)
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you want to solve for 'x' , right ? use the property of log : \(\log A+\log B =\log AB\) on left side, so what you get for, ln(x+2)+ln(x) =...?
ln(2x+2)?
Or x^2+2x?
x (x+2) = x*x + 2*x = x^2 +2x :) so you get ln (x^2+2x) = ln 35 so now can you solve the quadratic equation x^2+2x=35 ??
ln(x+2)+ln(x) =ln 35 ---> x^2+2x=35 because if ln A =ln B, then A=B
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so ? could you calculate values of x ?
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