Question

progam that inputs a char and dislpays wether it is digit or not using logical and condition operators in c++

Answer 1

what have you done?

Answer 2

write progam in c++

Answer 3

ans????

Answer 4

#define yes 1
#define no 0

#include <iostream.h>

int main(void)
{
char c[30];
int arr_size, result, i=0, state;
cin>>"Enter your digit:= ";
cout<<c<<endl;

arr_size=(sizeof(c)/sizeof(c[0]));

for(i; i < arr_size; i++)
{
if(check_digit(c[i]))
state = yes;
else
state = no;
}

if(!state)
cout<<It's not a digit<<endl;
else
cout<<It's a digit<<endl;

system("\npause");
return 0;
}
enjoy..

int check_digit(char c)
{
return (c>='0' && c<='9');
}

Answer 5

#define yes 1
#define no 0
#include <iostream.h>
int main(void)
{
char c[30];
int arr_size, result, i=0, state;
cin>>"Enter your digit:= ";
cout<<c<<endl;
arr_size=(sizeof(c)/sizeof(c[0]));
for(i; i < arr_size; i++)
{
if(check_digit(c[i]))
state = yes;
else
state = no;
}
if(!state)
cout<<It's not a digit<<endl;
else
cout<<It's a digit<<endl;
system("\npause");
return 0;
}

int check_digit(char c)
{
return (c>='0' && c<='9');
}