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An urn contains 10 white balls and 5 blue balls. Draws are made repeatedly from the urn as follows. On each draw, a ball is drawn and its color noted; then it is replaced in the urn along with 3 more balls of its color. Find the chance that the second ball drawn is blue, given that the first ball drawn is blue.
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First we have 10 white balls and 5 blue balls. After drawing a blue ball, recall it is replaced and then supplemented with 3 more blue balls -- so now we have 10 white balls and 8 blue balls. The probability that the next draw yields blue is then merely \(\dfrac8{18}=\dfrac49\)
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