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OpenStudy (anonymous):
I toss a coin 4 times. Find the chance of getting 2 heads.
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OpenStudy (raden):
it means the probability of P(2H and 2T) first, find the number events of HHTT, are 4!/(2!2!) = 6 we knowed that the probability of head event = 1/2 also tail even = 1/2 and it is independent, so, it can be P(2H and 2T) = 6 * 1/2 * 1/2 * 1/2 * 1/2 = 6/16 = 3/8
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