Question

hi everyone.c++ help . If am having an integer eg 1234567 "input 'NOT ALWAYS THE CASE THAT I WILL HAVE 7 INTEGERS INPUT' " how can i put this integer inside an array .The problem is that the integers may varies this means that a don't have the actual length of the integer that i can use it in my array as the size, so how am I going to do this.

Answer 1

@slotema

Answer 2

So basically you want to read any size of integer from the command line?

int d;
cin >> d;

should work, or am I missing something?

Answer 3

int number;
cin>>number;
//how am i going to find the length of the number that have been entered and assign the length to a certain variable that will work as my size inside my array,.actually this is like making the dynamic array but i want at the same time to take the actual input number inside the array.

Answer 4

you could calculate the length of a number by simply dividing it by 10 (or whatever your base is) until the result of the division becomes 0.

E.g. 123: 123 / 10 = 12; 12 / 10 = 1; 1 / 10 = 0, so the length of the number is 3.

Answer 5

so what if the user enters 5489766245566 how to find the length .
This is more like if i am using string eg typing in reginald i can use the function myvariable.length so how to do this when i am having an integer

Answer 6

using dynamic array i don't know how to take the input number to my array

Answer 7

Do you perhaps have a bit of code that's showing your problem? 'Cause I'm not sure what you want, to be honest.