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Mathematics 24 Online
OpenStudy (anonymous):

Can someone please help me with this? I don't really understand how to resolve the forces! -Attached

OpenStudy (perl):

resolve forces? you posted an algebra attachment

OpenStudy (anonymous):

OpenStudy (anonymous):

I'm sorry.

OpenStudy (perl):

wrong attachment?

OpenStudy (anonymous):

Yep. I attached the correct one.

OpenStudy (amistre64):

|dw:1366481198604:dw| im not too sure what the bead is for .... but as i see it, there are 2 equal forces in the downward direction that are each, half the weight of the ring (F = mg/2) knowing the Force down is proportional to the lengths of the corresponding triangles: 30*n = Force down 50*n = Force in string (tension)

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