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OpenStudy (zzr0ck3r):
f:A -> A x B, defined by f(x) = (x, b), where be is a fixed element in of B is f bijective? if so prove it.
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OpenStudy (zzr0ck3r):
does not seem to be onto unless B has one element....am I understanding that wrong?
OpenStudy (zarkon):
you are correct
OpenStudy (zzr0ck3r):
ok then I think I got it from here. ty
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