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Mathematics 19 Online
OpenStudy (anonymous):

sin2x=cos3x.sin2x

OpenStudy (anonymous):

1=cos3x now finish this

OpenStudy (anonymous):

by the way , is it \(sin^2x=cos^3x sin^2x\) or \(sin2x=cos3x sin2x\) ?

OpenStudy (anonymous):

so : \(1=cos^3x\) from here : \(cosx=1\) and the answer is: \(0+2m\pi\)

OpenStudy (anonymous):

answer should be 1/2mpi , 2/3mpi

OpenStudy (anonymous):

bud I donť know how go to answer

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