Question

solve for x

Answer 1

http://www.wolframalpha.com/input/?i=sin^-1%28x%29+%2B+sin^-1%286sqrt%283%29x%29+%3D+-pi%2F2

Is that right?

Answer 2

\[\sin^{-1} -(\frac{1}{2})+\sin^{-1} -(\frac{\sqrt{3}}{2})=-\frac{\pi}{2}\]
Therefore
\[-\frac{1}{2}=6x\]
\[x=-\frac{1}{12}\]