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solving the derivative of
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\[\frac{ 1-(e^x \times x) }{ x+e^x }\]
I first used the QUOTIENT RULE. After that I used the product rule for where it stipulates in the quotient formula to find the derivative of \[e^x \times x\]
\[\frac{ (x+e^x) \times( \frac{ d }{ dx }[1-e^x.x]) - (\frac{ d }{ dx }[x+e^x]) \times(1-e^x.x) }{ (x+e^x)^2 }\]
so its correct go on
give me 2 minutes please. typing out working
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\[(x+e^x)\left\{ (\frac{ d }{ dx }-e^x).x+(\frac{ d }{ dx }x)(-e^x.x)\right\} - (e^x+1)(1-e^x.x)\]
where the braces are, i implemented the product rule to derive: \[\frac{ d }{ dx }(1-e^x.x)\]
so its solved
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