Question

Find the specified nth term in the expansion of the binomial. (7a + 6b)^5, n = 5

Answer 1

(7a+6b)^5
= 5C0(7a)^5(6b)^0 + 5C1(7a)^4(6b)^1 + 5C2(7a)^3(6b)^2 +
5C3(7a)^2(6b)^3 + 5C4(7a)^1(6b)^4 + 5C5(7a)^0(6b)^5