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Mathematics 8 Online
OpenStudy (anonymous):

suppose the velocity of a particle moving in a line is v(t) =t^2-2t-8. find the displacement and distance traveled from 1<=t<=6. answer is -10/3 and 98/3 respectively, how?

OpenStudy (ash2326):

Integral of V is displacement, let it be x \[x=\int_1 ^ 6 (t^2-2t-8) dt\] Can you try to solve this?

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