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Suppose that AD,BC,AC and BD are line segments with line AD parallel to line BC as shown in the figure. If AD=3 units, BC=1 unit, and the distance from AD to BC is 5 units, find the altitude of the smaller triangle.
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i'm confuse at this question.
The sum of the areas of the two triangles will be = 1/2 (3+1)*5 = 10 sq units
can you please elaborate it??
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