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Mathematics 21 Online
OpenStudy (anonymous):

REALLY NEED HELP STUDYING FOR THIS SHIZZLE...

OpenStudy (anonymous):

The area of a right triangle is 30mm squared. The height is 12mm. Find the perimetier

OpenStudy (anonymous):

Area = 1/2 (b*h) 30 = 1/2 (b * 12) 60 = b*12 b = 5 5^2+ 12^2 = 169 c = 13 perimeter = 12+5+13 = 30

OpenStudy (anonymous):

any questions?

OpenStudy (anonymous):

holy mother of duck THANKK YUUUUUU

OpenStudy (anonymous):

wait how did u get 60???

OpenStudy (anonymous):

The area of a right triangle is 30mm squared. The height is 12mm. Find the perimetier

OpenStudy (anonymous):

|dw:1366590465299:dw| S=AB*BC/2 30=12*BC/2 multiply both sides by 2 60=12*BC

OpenStudy (anonymous):

thats how he got 60 in part of his calculations

OpenStudy (anonymous):

okk... How about this onee... the garden in front of Gemetry Middle School is in the shape of an isoceles trapezoid whos bases are 30m and 60m, respectively with a height of 1 m. The administration would like to put a fence around the garden. How many meters of fence will they need?

OpenStudy (anonymous):

you would better ask it as a new questions

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