Question

x^3-2x^2-3x+6 Can you show me the steps on how to find the zeros.

Answer 1

Did you use trial by error before?

Answer 2

no

Answer 3

x^3-2x^2-3x+6

= x² ( x - 2 ) - 3 ( x - 2 )

Note that (x-2) is a common factor.

Answer 4

x² ( x - 2 ) - 3 ( x - 2 ) =

(x - 2) * ( x² - 3)

Answer 5

(x - 2) * ( x² - 3) = 0

x - 2 = 0 OR ( x² - 3) = 0

Solve each of the two above equations for x.