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Precalculus 12 Online
OpenStudy (anonymous):

What is the vertices of the hyperbola x^2/36 - y^2/9=1

OpenStudy (anonymous):

(6,0) and (-6,0) you look at the first term x^2/36 take square root of the 36

OpenStudy (anonymous):

you get what A^2 is and find what A is and that's your vetcies

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