Question

Two planes which are 1060 miles apart , leave at the same time and fly toward each other , meeting in 4 hours . If their rates differ by 15 miles per hour , what is the rate of each plane ?

Answer 1

let x be slower plane
x+15 faster plane
from distance formula
distance = rate x time

d = 1060 4hrs = time
1060 = 4x + 4(x+15)
1060 = 4x + 4x + 60 subtract 60 from both sides of equation
1000 = 8x
x = 125 slow plane
x= 140 fast plane

check 4 x 125 = 500
4 x 140 = 560
500 + 560 = 1060

checks --but these are some slow panes!!!!!!!!!!!!!