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Algebra
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What are the x– and y–intercepts of the graph of y = 2x2 + 6x + 4?
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y=4 x=-2 and x=-1
thanks
2x^2+6x+4=0 2(x+2)(x+1)=0 x=-2 or x=-1 and x=0 y=2*0^2+6*0+4=4
could you helpme with a few more
Solve. 2x2 – 8x – 12 = 0 x = 1 ± 2 x = 2 ± x = 2 ± x = 2 ± 2
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2(x^2-4x-6)=0 x=2+sqrt10 or x=2-sqrt10
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