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OpenStudy (anonymous):
EASY AGAIN. solve 4sinx=cosec x . how ??? help me
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OpenStudy (gorv):
@Ika_Kim 4sinx=1/sinx 4(sinx)^2=1 sinx=(1/4)^1/2 sinx=+-1/2 remember sinx not equal to 0
OpenStudy (anonymous):
ohh,,, we can just use square root
OpenStudy (anonymous):
okayyy thankss ^_^ i got it
OpenStudy (gorv):
@Ika_Kim yes plzz click best response if u understood it
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