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HELP MULTIPLE CHOICE. WILL BECOME FAN.
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@amistre64 can you help me on these too? It just is confusing for me how to set up the equations..
b can be found by cosine rule ie $$\cos B=\frac{a^2+c^2-b^2}{2ac}$$
I can't seem to find the side length?
@BAdhi
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use the equation all the values are provided except the value of b
I get 0.75 = 1 - b ^ 2? HELP PLEASE :C
$$2ac \cos B= a^2+c^2-b^2\\ 2(12)(13)(\cos 41)=12^2+13^2-b^2\\ b^2=12^2+13^2-235.46$$
I got the 3rd one?
What about the next question I had? @BAdhi
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your know all the sides of the triangle now find the angles using cosine rule
alright
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