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Mathematics 19 Online
OpenStudy (anonymous):

HELP MULTIPLE CHOICE. WILL BECOME FAN.

OpenStudy (anonymous):

OpenStudy (anonymous):

@amistre64 can you help me on these too? It just is confusing for me how to set up the equations..

OpenStudy (badhi):

b can be found by cosine rule ie $$\cos B=\frac{a^2+c^2-b^2}{2ac}$$

OpenStudy (anonymous):

I can't seem to find the side length?

OpenStudy (anonymous):

@BAdhi

OpenStudy (badhi):

use the equation all the values are provided except the value of b

OpenStudy (anonymous):

I get 0.75 = 1 - b ^ 2? HELP PLEASE :C

OpenStudy (badhi):

$$2ac \cos B= a^2+c^2-b^2\\ 2(12)(13)(\cos 41)=12^2+13^2-b^2\\ b^2=12^2+13^2-235.46$$

OpenStudy (anonymous):

I got the 3rd one?

OpenStudy (anonymous):

What about the next question I had? @BAdhi

OpenStudy (badhi):

your know all the sides of the triangle now find the angles using cosine rule

OpenStudy (anonymous):

alright

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