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OpenStudy (anonymous):
The probability that bridge A will fail an inspection is 0.08 and for bridge B the probability is 0.06. The probability they will both fail is 0.02. What is the probability that at least one will fail the inspection?
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OpenStudy (anonymous):
\(0.08+0.06-0.02\) as \[P(A\cup B)=P(A)+P(B)-P(A\cap B)\]
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