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OpenStudy (anonymous):

According to the video, if an object falls five meters during the first interval of time, what is the total distance fallen at the end of the second interval of time?

OpenStudy (anonymous):

|dw:1366660744676:dw| we assume the initial velocity to be \(v_0\)\[s=v_0t+{1\over2}at^2\\ 5=v_0+4.95\implies v_0=0.05\\ \;\\ s=v_0t+{1\over2}at^2\\ s=0.05(2)+{1\over2}(9.81)(2^2)=? \]

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