Question

The length of a rectangle is 4yd longer than its width.
If the perimeter of the rectangle is 48yd, find its area.

Answer 1

the P of a rectangle is the sum of all 4 sides or is generaly written as:
2*l + 2*w = P and area is wrtten as l*w.
.
The question states the following to be true:
Let w represent the width
l = (w + 4)
.


2*(w + 4) + 2*w = 40yds
.
Simplify and solve for w
4w + 8 = 48yds
4w = 40yds
w= 10 yds
l = 14yds
.
A = l*w
A=14*10
A=140 yd^2