OpenStudy (anonymous):

....

4 years ago
OpenStudy (anonymous):

@Mertsj thanks for being here, get go, please

4 years ago
OpenStudy (mertsj):

Let's start out by discussing the major and minor axes and how they relate to the equation. Does that sound familiar?

4 years ago
OpenStudy (mertsj):

Do you know that the length of the major axis is 2a?

4 years ago
OpenStudy (mertsj):

\[\frac{x^2}{a^2}+\frac{y^2}{b^2}=1\]

4 years ago
OpenStudy (mertsj):

That is the equation of a horizontal ellipse whose center is the origin

4 years ago
OpenStudy (mertsj):

It turns out that a is the distance from the center to the vertex. And b is the distance from the center to the co-vertex.

4 years ago
OpenStudy (mertsj):

So that means that the length of the major axis is 2a and the length of the minor axis is 2b.

4 years ago
OpenStudy (mertsj):

That is what part a of your problem is asking about.

4 years ago
OpenStudy (mertsj):

Yes.

4 years ago
OpenStudy (mertsj):

Part b wants you to note that the numerators of the fractions are x^2 and y^2 since \[\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1\] h and k are both 0 if the center is the origin.

4 years ago
OpenStudy (mertsj):

And finally part c is to actually write the equation. Can you do that now?

4 years ago
OpenStudy (mertsj):

Yes. Good job!!

4 years ago
OpenStudy (mertsj):

yw

4 years ago