OpenStudy (anonymous):

Is x - 8 a factor of the function f(x) = -2x3 + 17x2 - 64? Explain. A. Yes. When the function f(x) = -2x3 + 17x2 - 64 is divided by x - 8, the remainder is zero. Therefore, x - 8 is a factor of f(x) = -2x3 + 17x2 - 64. B. No. When the function f(x) = -2x3 + 17x2 - 64 is divided by x - 8, the remainder is zero. Therefore, x - 8 is not a factor of f(x) = -2x3 + 17x2 - 64. C. Yes. When the function f(x) = -2x3 + 17x2 - 64 is divided by x - 8, the remainder is not zero. Therefore, x - 8 is a factor of f(x) = -2x3 + 17x2 - 64. D. No. When the function f(x) = -2x3 + 17x2 - 64 is divided

4 years ago
OpenStudy (campbell_st):

well the easy thing to do is use the factor theorem if (x - 8) is a factor then x = 8 should result in f(8) being zero.. so just substitute \[f(8) = -2(8)^3 + 17(8)^2 - 64\] hope this helps.

4 years ago
OpenStudy (anonymous):

So (x - 8) is a factor, and I just have to use Long Division of Polynomials to figure it out?

4 years ago
OpenStudy (campbell_st):

well yes... its a bit of a tedious process when you can use the factor theorem to prove it. I'd ask your teacher why you can't use the factor theorem to show it.

4 years ago
OpenStudy (anonymous):

4 years ago
OpenStudy (anonymous):

You guys rock! Thanks! :D

4 years ago
OpenStudy (campbell_st):

glad to help

4 years ago
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