Question

can anybody help with algebra 1

Answer 1

http://ocas.pearsonschool.com/ph/cd/0-13-365946-8/index.html?pageid=281&token=53616c7465645f5f81d8086b402612535c05bb36548c352efd4d42aa1f0bb0bdac910c59b0106743211d5f73e68757a01aa7c21cd8986203d225aa23afe42a72ef07f866009a4e4b

Answer 2

what is your question?

Answer 3

i sent the link its on page 280 task 3

Answer 4

@master43 do you have algebra 1in CA

Answer 5

the length of the necklace is the "independent variable"
it determines the length of the string

Answer 6

10 inches of necklace requires 200 inches of string, and each additional inch of necklace requires two additional inches of string
making it linear

Answer 7

so a 15 inch necklace should require 210 inches of string

Answer 8

thank you and witch one is a b c or d cuze it has four steps to do?

Answer 9

@satellite73

Answer 10

i was looking at page 280 task 3 right?

Answer 11

yes you where and they are asking to do 4 things that are marked as a b c d

Answer 12

ok lets do them one by one

Answer 13

ok:)

Answer 14

a) identify the "independent" and "dependent" variable
the "independent variable" is the length of the necklace
the "dependent variable" is the amount of string used

Answer 15

ow ok and the rest

Answer 16

b) write the graph as a "function rule"
you could say in english "ten inches of necklace requires 200 inches of string, and each additional inch of necklace takes two more inches of string"
or, you could say if \(n\) is then inches of necklace then the mount of string used is
\[2n+180\]

Answer 17

c) if you just plot the points given, the graph is "discrete" but if you connect the dots, it is "continuous"

Answer 18

d) for a 15 inch necklace you would need \(2\times 15+180=30+180=210\) inches of string

Answer 19

omg thank you so much

Answer 20

yw