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Mathematics 20 Online
OpenStudy (anonymous):

x3 + x2 – x – 1 factor the expression.

OpenStudy (anonymous):

\[x^3 + x^2 – x – 1\]

OpenStudy (anonymous):

(x-1)(x+1)^2

OpenStudy (anonymous):

\[x^3 + x^2 – x – 1\] \[(x-1) (x+1)^2\]

OpenStudy (anonymous):

these are the answers A.(x2 + 1)(x – 1)B.(x + 1)(x + 1)(x – 1)C.(x2 – 1)(x – 1)D.(x – 1)(x – 1)(x + 1) @some_someone

OpenStudy (anonymous):

well okaii then: \[(x-1) (x+1)^2\] \[(x-1) (x+1) (x+1)\]

OpenStudy (anonymous):

since the (x+1)^2 you do (x+1)(x+1). so (x +1)(x+1)(x-1)

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