Question

This is an Geometric Problem

A lot is in the shape of a triangle . One side is 32 feet longer than the shortest side while the third side is ten feet shorter than twice the shorter side . The perimeter of the lot is 238 feet . Find the length of the sides of the lot .

Answer 1

i think it is just an algebraic problem :) lolz
let the shortest side be x
then try to write all other sides in terms of x then sum of all is given 238 feet so x can be solved :)

Answer 2

try if any problem persist i will help you :)

Answer 3

can you solve this question ?

Answer 4

smallest side=x
one side=x+32
other side=2x-10
so sum of all side i.e. perimeter=x+x+32+2x-10=4x+22
but sum is given=238
4x+22=238
4x=238-22=216
x=216/4=54feet
so smallest side=54 feet
one side=54+32=86 feet
other=2*54-10=108-10=98 feet :)

Answer 5

so the answer is 98 feet ...

Answer 6

x=shortest side
x+32=another side
(2x-10)=final side
perimeter = 238
so--x+x+32+2x-10=238
4x=213
x=54,,,,x+32=86,,,,2x-10=98...........54+86+98=238