Question

Find an approximate solution to the equation 10^(2x-1)=5.
a. 1.0674
b. 0.8945
c. 2.7081
d. 6.6974

Answer 1

start with
\[2x-1=\log(5)\] then solve as you would any linear equation
add 1, divide by 2

\[2x-1=\log(5)\]
\[2x=\log(5)+1\]
\[x=\frac{\log(5)+1}{2}\]
now to get a decimal you will need a calculator

Answer 2

I got 0.849485002168.

Answer 3

yeah me too