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Algebra 16 Online
OpenStudy (anonymous):

cos2u=cos^2u-sin^2u

OpenStudy (anonymous):

hi

OpenStudy (anonymous):

wait y did you delete it

OpenStudy (anonymous):

thanks

OpenStudy (anonymous):

wait wait i think i did some wrong calculations wait !

OpenStudy (anonymous):

omg lol

OpenStudy (anonymous):

@antoni7 wont it rather be \[\cos 2u=\cos ^{2}u-(1-\cos ^{2}u)\]

OpenStudy (anonymous):

\[\cos 2u=\cos ^{2}u-1+\cos ^{2}u\]

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