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solve the quadratic equation y^2-7y-18=0 by factoring
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x= -2 x=9
err Y I mean.
a= 1, b= -7, c= -18 x = [– b ± √b² – 4ac]/2a now u can solve it right
y ^{2}-9y+2y-18=0 thus y(y-9)+2(y-9)=0 thus (y+2)(y-9)=0 hence y=9 ; x=-2
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