Question

Simplify. Assume the divisor is not zero.

(8x2y2 – 4xy) ÷ 4xy



A.


2xy – y


B.


2xy


C.


xy – 1


D.


2xy – 1

Answer 1

Nurali Kinda need help in my history do i type it in the history?

Answer 2

\[\frac{ 8x^2y^2 -4xy}{ 4xy }\]

\[\frac{ 8x^2y^2 }{ 4xy }-\frac{ 4xy }{ 4xy }\]

\[2x ^{2-1}y ^{2-1}-1\]

\[2xy – 1\]

Answer 3

2xy-1