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A die is rolled 12 times. Find the chance that the face with six spots appears once among the first 6 rolls, and once among the next 6 rolls.
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The first six rolls and the next six are independent events. So the final probability = P1 * P2. Also both are exactly identical so their probabilities will be same. P1= P2 Now do u knw the bernoulli's trials formula to compute the prob of getting a 6 exactly once in 6 identical trials?
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