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make p the subject of the formula q=5/3+p
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\[q=\frac{ 5 }{ 3+p }\] \[\frac{ 1 }{ q }=\frac{ 3+p }{ 5 }\] \[\frac{ 5 }{ q }-3=p\] \[p=\frac{ 5-3q }{ q }\]
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