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OpenStudy (anonymous):
A box contains 129 red candies and 42 yellow candies if you draw 1 candy at random whats the probability, to the nearest percent, that's red?
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OpenStudy (anonymous):
it's just 129/(129+42) which is 129/171 which is... 75.438% which about equals to the nearest percent 75%.
OpenStudy (anonymous):
thank you!
OpenStudy (anonymous):
Youre welcome! Happy to help.
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