Question

Find the absolute (global) Maximum and absolute (global) Minimum values of the function f(x)= (x^2)/(x^2-9) on the interval [-2,1].

Answer 1

start by finding the critical numbers of \(f\)

Answer 2

(-3,3)?

Answer 3

no

Answer 4

there is only one critical number

Answer 5

oh! it's 0

Answer 6

correct

Answer 7

and 0 falls between -2 and 1 so we keep it

Answer 8

now plug -2,0, and 1 into \(f\)

which is the biggest and which is the smallest

Answer 9

f(-2)= -4/5 f(0)=0 f(1)=-1/8