Question

6x^2+5x-1

Answer 1

I suppose is,
\[6x^2+5x-1=0\Rightarrow x=\frac{-5\pm\sqrt{5^2-4\cdot6\cdot(-1)}}{2\cdot6}=\frac{-5\pm7}{12}\]
So the solutions are,
\[x_1=2/12=1/6;\ x_2=-12/12=-1\]

Answer 2

(6x-1) (x+1)