I need to find the points of inflection and discuss the concavity of the graph of the function below. I am stuck is there anyone that can help me please?
f(x)=2x^3-3x^2-12x+5

Question

I need to find the points of inflection and discuss the concavity of the graph of the function below. I am stuck is there anyone that can help me please?
f(x)=2x^3-3x^2-12x+5

anonymous · Answer

f'(x)=6x^2-6x-12

anonymous · Answer

f"(x)=12x-6 and when i solve for x when set equal to 0 I get x=1/2

anonymous · Answer

but I'm having trouble with coming up with my intervals

anonymous · Answer

http://www.youtube.com/watch?v=Q81gafPM5y8

anonymous · Answer

I thought that you used your values for x to make your intervals but since i don't have multiple values for x then can i just make up some and choose test values within those limits?

anonymous · Answer

okay i'm going to watch it

anonymous · Answer

thank you

anonymous · Answer

yes, watch it and if still you have trouble with it i will help you.
since i forgot some of the stuff in calculus thats why i refered this video to you.

anonymous · Answer

okay thanks

anonymous · Answer

you are welcome