An object moves along x-axis. Its position at time t is given by: x(t) = t^3 - 7t^2 + 10t +8, 0

Question

An object moves along x-axis. Its position at time t is given by: x(t) = t^3 - 7t^2 + 10t +8, 0<t<5. Determine the velocity function, the acceleration function, and when the acceleration becomes zero?

amistre64 · Answer

taking derivatives of polynomials is the most basic application

amistre64 · Answer

x'(t) = velocity

x''(t) = acceleration

x''(t) = 0, for what value of t?

anonymous · Answer

Thank you for the help I can do those on my own I was just confused on how to answer the question. t is either greater than or = to 0 and less than or equal to 5

amistre64 · Answer

if you need help sorting it out any more, just holla! ... thats what the kids say these days right?