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Mathematics 7 Online
OpenStudy (anonymous):

can any one answer it

OpenStudy (anonymous):

?

OpenStudy (anonymous):

there will be \[{P^7_3\over3!}=\frac{7!}{3!(7-3)!}=\frac{7\times6\times5}{3\times2}=35\] number of sets of these, how many have non-repeating pairs?

OpenStudy (anonymous):

there is no repeating one

OpenStudy (anonymous):

of these "3" element sets, how many are unique, in the sense that they do not have "2" common elements

OpenStudy (anonymous):

okay

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